QA-P42: QA-Orthopole Center


QA-Tf3 is the QA-Orthopole Transformation that transforms a random point Q0 into another point Q1. This point Q1 can again be transformed by QA-Tf3 into another point Q2, etc..

The lines Qi.Qi+2 and Qi+1.Qi+3 intersect in a fixed point independent of starting point Q1.

Stated in another way: the consecutive generation points Qi diverge oscillating from a fixed point. This point will be called QA-P42.

Infovisual QA-P42-infovisual-cvt-01.png

Another interesting and related property is the similarity of Triangles of QA-points and their QA-Tf3-image:

Infovisual QA-P42-infovisual-cvt-02.png

There is also a second major construction for this point.

The 4 centers of the circles through the pedal points of Quadrangle point Pi wrt Triangle Pj.Pk.Pl where (i,j,k,l) ∈ (1,2,3,4) form a QA-Pedal Quadrangle.

QA-P42 is the Homothetic Center of the 2nd generation QA-Pedal Quadrangle and the Reference Quadrangle.

The homothecy coefficient equals (2 cos α)2 , where α is the angle formed by the asymptotes of QA-Co1 (this holds for convex quadrangles; a similar formula holds for the non-convex case). See [36], pages 348,349.

Infovisual QA-P42-infovisual-cvt-03.png
1st CT-Coordinate

a2 q r (a2 q r + 3 c2 p q + 3 b2 p r) + 2 p2 (b2 SC r2 + c2 SB q2 + 2 S2 q r)

1st DT-Coordinate

a4 (p2 – q2) (p2 – r2) + b2 c2 p2 (p2 + q2 + r2)

+ b2 p2 (p2 – q2) (b2 – 2 a2) + c2 p2 (p2 – r2) (c2 – 2 a2)

Properties
  • where (CT-coordinates):
  • m = (2 (c2 p q + b2 p r + a2 q r)2 – 8 p q r S2 (p + q + r))/ ( (c2 p q + b2 p r + a2 q r)2 + 12 p q r S2 (p + q + r))
  • n = ( (c2 p q + b2 p r + a2 q r)2 – 4 p q r S2 (p + q + r))/ (-4 (c2 p q + b2 p r + a2 q r)2)
  • Triangle X.QA-P42.Y is similar to Triangle QA-Tf3(X).QA-P42.QA-Tf3(Y), so:
  • Angle(QA-P2.QA-P42.QA-P11) = Angle(QA-P4.QA-P42.QA-P12).
  • The QA-Orthopole(QA-Tf3) of QA-P42 is QA-P42.
  • QA-P42 is the perspector of the QG-P12 Triple Triangle and the QL-P26 Triple Triangle.
  • QA-P42 is collinear with QA-P1 and the reflection of QA-P4 in QA-P3. See [34], Eckart Schmidt, QFG-message #1666.



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